(x^2-25)/((x+5)^2)*(2x-10)/(4x-20)

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Solution for (x^2-25)/((x+5)^2)*(2x-10)/(4x-20) equation: 


D( x )

4*x-20 = 0

(x+5)^2 = 0

4*x-20 = 0

4*x-20 = 0

4*x-20 = 0 // + 20

4*x = 20 // : 4

x = 20/4

x = 5

(x+5)^2 = 0

(x+5)^2 = 0

x+5 = 0 // - 5

x = -5

x in (-oo:-5) U (-5:5) U (5:+oo)

(((x^2-25)/((x+5)^2))*(2*x-10))/(4*x-20) = 0

((x^2-25)*(2*x-10))/((x+5)^2*(4*x-20)) = 0

( 2*x-10 )

2*x-10 = 0 // + 10

2*x = 10 // : 2

x = 10/2

x = 5

( x^2-25 )

1*x^2 = 25 // : 1

x^2 = 25

x^2 = 25 // ^ 1/2

abs(x) = 5

x = 5 or x = -5

x in { 5} 

x in { -5} 

x belongs to the empty set

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